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In the circuit shown in the figure, if switches S1 and S2 have been closed for a long time, then charge on the  capacitor

a
1s 100  μC
b
increases to 200  μC if one third of the gap of the capacitor's plates is filled with a dielectric (K = 2) of same area
c
remains unchanged if one third of the gap of the capacitor's plates is filled with,a dielectric (K = 2) of same area.
d
both (1) and (2)

detailed solution

Correct option is D

After long time, current through the capacitor = 0 Current through 6  Ω   resistor,  i=12−48 =1AVoltage across capacitor, V = 4 + (6) (1) = 10 VCharge on the capacitor, Q=10 10 = 100 μCAfter the insertion of dielectricC'=Aε0d3+d3+d32  =  Aε0d  113 +13 +16 =10  15/6 = 65 10=12  μFHere voltage across capacitor remains same.∴   Charge  on  the  capacitor,  Q'=12 10 = 120 μC

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