In the circuit shown in the figure, if switches S1 and S2 have been closed for a long time, then charge on the capacitor

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

1s 100 μC

increases to 200 μC if one third of the gap of the capacitor's plates is filled with a dielectric (K = 2) of same area

remains unchanged if one third of the gap of the capacitor's plates is filled with,a dielectric (K = 2) of same area.

both (1) and (2)

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

After long time, current through the capacitor = 0 Current through 6 Ω resistor, i=12−48 =1AVoltage across capacitor, V = 4 + (6) (1) = 10 VCharge on the capacitor, Q=10 10 = 100 μCAfter the insertion of dielectricC'=Aε0d3+d3+d32 = Aε0d 113 +13 +16 =10 15/6 = 65 10=12 μFHere voltage across capacitor remains same.∴ Charge on the capacitor, Q'=12 10 = 120 μC

Watch 3-min video & get full concept clarity