First slide

Transistor

Question

In the circuit shown in the figure, the input voltage $V_{i}$ is 20 $V_{B E} = 0$ and $V_{C E} = 0$ . The values of $I_{B}, I_{C} and β$ are given by

Moderate

A

$I_{B} = 40 μ A, I_{C} = 10 mA, β = 250$
B

$I_{B} = 25 μ A, I_{C} = 5 mA, β = 200$
C

$I_{B} = 20 μ A, I_{C} = 5 mA, β = 250$
D

$I_{B} = 40 μ A, I_{C} = 5 mA, β = 125$

Solution

Given $V_{B E} = 0$
$V_{C E} = 0$

$∴$ Collector current,
$I_{C} = \frac{(20 - 0)}{4 \times 10^{3}}$
$\begin{array}{l} or I_{C} = 5 \times 10^{- 3} A = 5 mA \\ Input voltage, V_{i} = V_{B E} + I_{B} R_{B} \\ or V_{i} = 0 + I_{B} R_{B} or 20 = I_{B} \times 500 \times 10^{3} \\ ∴ I_{B} = \frac{20}{500 \times 10^{3}} = 40 μ A \end{array}$
$∴ Current gain, β = \frac{I_{C}}{I_{B}} = \frac{5 \times 10^{- 3}}{40 \times 10^{- 6}} = 125$

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