Questions
In the circuit shown in the figure, the input voltage is 20 and . The values of are given by
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Correct option is D
Given VBE=0VCE=0 ∴Collector current,IC=(20-0)4×103 or IC=5×10-3 A=5 mA Input voltage, Vi=VBE+IBRB or Vi=0+IBRB or 20=IB×500×103∴ IB=20500×103=40μA∴ Current gain, β=ICIB=5×10-340×10-6=125
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In a common-base mode of transistor, the collector current is 5 488 mA for an emitter current of 5 .60 mA. The value of the base current amplification factor (p) will be
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