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In the circuit shown in the figure, the input voltage $V_{i}$ is 20 $V_{B E} = 0$ and $V_{C E} = 0$ . The values of $I_{B}, I_{C} and β$ are given by

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IB=40μA,IC=10 mA,β=250

IB=25μA,IC=5 mA,β=200

IB=20μA,IC=5 mA,β=250

IB=40μA,IC=5 mA,β=125

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detailed solution

Correct option is D

Given VBE=0VCE=0 ∴Collector current,IC=(20-0)4×103 or IC=5×10-3 A=5 mA Input voltage, Vi=VBE+IBRB or Vi=0+IBRB or 20=IB×500×103∴ IB=20500×103=40μA∴ Current gain, β=ICIB=5×10-340×10-6=125

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In the circuit shown in the figure, the input voltage Vi is 20 VBE=0 and VCE=0. The values of IB,IC and β are given by

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In the circuit shown in the figure, the input voltage $V_{i}$ is 20 $V_{B E} = 0$ and $V_{C E} = 0$ . The values of $I_{B}, I_{C} and β$ are given by