In the circuit shown in figure, potential difference between point A and B is 16 V. Find the current passing through 2 Ω resistance.
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a
1.5 A
b
3.5 A
c
1.0 A
d
2.5 A
answer is B.
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Detailed Solution
By applying KVL,VA−4I−9−I1+3−4I=VB16=+8I+I1 -68I +I1=10V …..(i)By applying KVL in loop A'B'C'D'A',−9−I1 +2 I−I1=0−3I1 +2I=9 …..(ii)By solving (i) and (ii) current in 2 Ω resistance is 3.5A.