In the circuit shown in figure, potential difference between point A and B is 16 V. Find the current passing through 2 Ω resistance.
1.5 A
3.5 A
1.0 A
2.5 A
By applying KVL,
VA−4I−9−I1+3−4I=VB16=+8I+I1 -68I +I1=10V …..(i)
By applying KVL in loop A'B'C'D'A',
−9−I1 +2 I−I1=0−3I1 +2I=9 …..(ii)
By solving (i) and (ii) current in 2 Ω resistance is 3.5A.