In the circuit shown in figure, R is a pure resistor, L is an inductor of negligible resistance (as$$ compared to $$R), S is a $$100$$ V $$50$$ Hz ac source of negligible resistance. With either key $$K1$$ alone or $$K2$$ alone closed, the current is $$I0$$. If the source is changed to $$100$$ V, $$100$$ Hz the current with $$K1$$ alone closed and with $$K2$$ alone closed will be, respectively,

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Infinity Learn · Accepted Answer

Current remains unchanged in R. However, it becomes half in L,because reactance is doubled on doubling the frequency.

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