First slide

CIrcuit questions

Question

In the circuit shown in figure resistance of galvanometer coil is $1 Ω$ . Then

Moderate

A

Current through the galvanometer G is zero
B

Reading of ammeter is 0.5 A
C

charged stored in the 5 $μ F$ capacitor is 30 $μ C$
D

Current through the galvanometer is 0.2 A

Solution

In steady state, $I_{g} = \frac{10}{4 + 1 + 5} A = 1 A$
Potential drop across the 5 $μ F$ capacitor = $(5 + 1) \times 1 v o l t = 6 v o l t . T h e r e f o r e c h a r g e s t o r e d = 6 \times 5 μ C = 30 μ C$

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