First slide

Electrical power

Question

In the circuit shown in figure, the resistance R can be varied. By changing R power dissipated in it is made maximum. If the emf of the battery is 10 volt and internal resistance is 1 ohm then find the maximum power dissipated in R.

Moderate

A

10 W
B

15 W
C

20 W
D

25 W

Solution

When power dissipated in R is maximum, $R = r = 1 Ω$
$∴ i = \frac{ε}{R + r} = \frac{10}{1 + 1} A = 5 A$
$∴$ Maximum power in $R = {(i)}^{2} R = {(5)}^{2} \times 1 W = 25 W$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App