Magnetic field due to a current carrying Element - Biot - Savart law
Question
In the circuit shown in figure. The ring is made of a wire of uniform cross-sectional area. If magnetic induction at the centre O produced by the segment ACB is 25µT, what will be the magnetic induction at O produced by the segment ADB ?
Moderate
Solution
Resultant magnetic induction at O is zero.
Since the lengths of ACB and ADB are in the ratio of 5:1. The currents will divide in the ratio 1:5. As a result the magnetic induction produced by the two arcs will be equal and opposite in direction cancelling each other.
Thus magnetic induction at center is equal to zero
magnetic induction produced by ADB
= magnetic induction produced by ACB
= 25 µT (outward)
Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Recieve an sms with download link
OR
SCAN ME
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
