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Questions  

In the circuit shown in figure, the switch S is closed at t = 0, when reading of the voltmeter is 8 volt, the energy stored in the inductor is [Given R=4ΩandL=10mH]

a
20 mJ
b
16 mJ
c
25 mJ
d
50 mJ

detailed solution

Correct option is A

V=iR⇒i=84A=2A∴ U = Magnetic energy stored in the inductor =12Li2=12×10×10−3×22J=20 mJ

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Two different coils have self-inductances L1 = 8 mH, L2 =2 mH. The current in one coil is increased at aconstant rate. The current in the second coil is also increased at the same rate. At a certain instant of time, the power given to the two coils is the same. At that time the current, the induced voltage and the energy stored in the first coil are i1 V1and W1 respectively. Corresponding value for the second coil at the same instant are i2, V2 and W2 respectively. Then


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