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Q.

In the circuit shown in figure, the switch S is closed at t = 0, when reading of the voltmeter is 8 volt, the energy stored in the inductor is [Given R=4Ω and L=10 mH]

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a

20 mJ

b

16 mJ

c

25 mJ

d

50 mJ

answer is A.

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Detailed Solution

V=iR⇒i=84A=2A∴ U = Magnetic energy stored in the inductor =12Li2=12×10×10−3×22J=20 mJ
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