Questions
In the circuit shown in the figure, terminal B is grounded and potential of terminal A is 10 volt. Then charge stored in Capacitor is
a
8μC
b
12μC
c
16μC
d
20μC
detailed solution
Correct option is B
(2)Since C1C3=C2C4, The given circuit is a balanced wheat stone bridge. So 5μF can be removed from the circuit. Now C'= C1 . C2C1+C2=2 × 32 × 3 μF=65 μF∴ Charge in 3μF capacitor = C' × 10−0=65× 10 μC=12μCTalk to our academic expert!
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