In the circuit shown in the figure, terminal B is grounded and potential of terminal A is 10 volt. Then charge stored in 3μF Capacitor is

(2)Since  C1C3=C2C4, The given circuit is a balanced wheat stone bridge. So 5μF can be removed from the circuit.  Now   C'=  C1 . C2C1+C2=2 × 32 × 3  μF=65    μF∴  Charge  in  3μF  capacitor = C' × 10−0=65× 10 μC=12μC