In the circuit shown in figure (1), the V0 ,I1 , ID1 , and  ID3 are respectively

Since applied voltage is greater than 0.7 V and direction of current is same as direction of arrow head, both the diodes are in “on” state (see above figure(2)). Now V0is parallel to D1 and D2. Hence V0=0.7 VCurrent I1=VRR=E−VDR=10V−0.7V0.33kΩ=28.18 mABothe the silecon diodes have similar characteristics.Hence  ID1=ID2=I12=14.09mA