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Q.

The circuit shown has been operating for a long time. The instant after the switch in the circuit labeled S is opened, what is the voltage (in volt) across the inductor VL ? Take R1=4.0Ω,R2=8.0Ω and L=2.5H

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answer is 6.00.

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Detailed Solution

Current in the inductor before opening ' S'I=124×84+8=92=4.5 ASince current in inductor does not change instantly, therefore, just after opening 'S',∴12+VL−IR1=0⇒12+VL−4.54=0⇒VL=6V

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