In the circuit shown here, E1=E2=E3=2V and R1 and R2 = 4 ohms. The current flowing between points A and B through battery E2 is
zero
2 A from A to B
2 A from B to A
None of the above
The given circuit can be redrawn as:
Eeq = E1R1 + E2R2 R1 + R2 = 2 × 4+2 × 44+4=2 V and
Req=42 = 2 Ω
Current, i=2+22=2 A from A to B through E2.