In the circuit shown here, E1=E2=E3=2V  and  R1 and  R2 = 4 ohms. The current flowing between points A and B through battery E2 is

The given circuit can be redrawn as:Eeq =  E1R1  + E2R2 R1 +  R2 = 2 × 4+2 × 44+4=2  V  andReq=42  =  2  ΩCurrent, i=2+22=2  A from A to B through E2.