Q.

The circuit shown here has two batteries of 8.0 V and 16.0 V and three resistors 3 Ω, 9 Ω and 9 Ω and a capacitor of 5.0μFHow much is the current I in the circuit in steady state?

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a

1.6 A

b

0.67 A

c

2.5 A

d

0.25 A

answer is B.

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Detailed Solution

In steady state capacitor is fully charged hence no current will flow through line 2 . By simplifying the circuitHence resultant potential difference across resistances will be 8.0 V Thus current I=VR=8.03+9=812 or I=23=0.67 A
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The circuit shown here has two batteries of 8.0 V and 16.0 V and three resistors 3 Ω, 9 Ω and 9 Ω and a capacitor of 5.0μFHow much is the current I in the circuit in steady state?