First slide

Ohm's law

Question

In the circuit shown here, the readings of the ammeter and voltmeter are (Ammeter and voltmeter are ideal)

Moderate

A

6 A, 60 V
B

0.6 A, 6 V
C

6/11 A, 60/11 V
D

11/6 A,11/60 V

Solution

The given circuit can be redrawn as follows:
Current, $i = \frac{6}{6 + 4 + 1} = \frac{6}{11} A$
Potential difference between A and B,
$V = \frac{6}{11} \times 10 = \frac{60}{11} V$

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