First slide

KVL

Question

In the circuit shown, if $(v_{a} - v_{b}) = 10 v o l t,$ find ‘r’

Easy

A

$2 Ω$
B

$1.5 Ω$
C

$0.5 Ω$
D

$1 Ω$

Solution

$\begin{array}{l} i = \frac{20 - 5}{2 + r} = (\frac{15}{2 + r}) A . \\ N o w, v_{a} - v_{b} = 20 - 2 i = (20 - \frac{30}{2 + r}) v o l t . \\ ∴ 20 - \frac{30}{2 + r} = 10 \Rightarrow r = 1 Ω . \end{array}$

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