Questions
In the circuit shown ln figure, a conducting wire HE is moved with constant a speed v toward left. the complete circuit is placed in a uniform magnetic field perpendicular to the plane of the circuit inward. The current in HKDE is
detailed solution
Correct option is D
Potential difference across capacitorV=Bvℓ= constant Therefore, charge stored in the capacitor is also constant.Thus, current through the capacitor is zero.Talk to our academic expert!
Similar Questions
The diagram shows a circuit having a coil of resistance and inductance L connected to a conducting rod PQ which can slide on a perfectly conducting circular ring of radius 10 cm with its centre at 'P'. Assume that friction and gravity are absent and a constant uniform magnetic field of 5 T exists as shown in figure.
At t = 0, the circuit is switched on and simultaneously a time varying external torque is applied on the rod so that it rotates about P with a constant angular velocity 40 rad/s. Find magnitude of this torque (in milli Nm) when current reaches half of its maximum value. Neglect the self-inductance of the loop formed by the circuit.
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