Questions
In the circuit shown, potential difference across the capacitor is
detailed solution
Correct option is D
Equivalent capacitance Ce=3×4+23+4+2μF=2 μF∴ Charge on 3μF capacitor, Q=CV=2×10 μC∴Potential difference across 3μF capacitor =2×103 volt = 6.66 volt∴ Potential difference across 4 μF capacitor =10−6.66 volt = 3.34 voltTalk to our academic expert!
Similar Questions
Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
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