First slide

Capacitance

Question

In the circuit shown, potential difference across the $4 μ F$ capacitor is

Moderate

A

7.27 V
B

2.34 V
C

4.42 V
D

3.34 V

Solution

Equivalent capacitance
$C_{e} = \frac{3 \times (4 + 2)}{3 + (4 + 2)} μ F = 2 μ F$
$∴$ Charge on $3 μ F$ capacitor, $Q = C V = 2 \times 10 μ C$
$∴$ Potential difference across $3 μ F$ capacitor $= \frac{2 \times 10}{3} volt = 6.66 volt$
$∴$ Potential difference across $4 μ F$ capacitor $= (10 - 6.66) volt = 3.34 volt$

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