Questions
In the circuit shown, sliding contact is moving with uniform velocity towards right. Its value at some instance is . The current in the circuit at this instant of time will be
detailed solution
Correct option is B
Since resistance of the circuit is increasing and hence current in the circuit is decreasing, so didt is negative. Current in the circuit is given by i=6-Ldidt12. Since didt is negative so the value of numerator will be more than 6 V and hence current in the circuit at that instant will be more than 0.5 A.Similar Questions
What happens when the switch is turned off in the adjoining figure which shows two bulbs B1 and B2, resistor R and an inductor L ?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests