Questions
In the circuit shown, sliding contact is moving with uniform velocity towards right. Its value at some instance is . The current in the circuit at this instant of time will be
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a
0.5 A
b
More than 0.5 A
c
Less than 0.5 A
d
May be less or more than 0.5 A depending on the value of L
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Correct option is B
Since resistance of the circuit is increasing and hence current in the circuit is decreasing, so didt is negative. Current in the circuit is given by i=6-Ldidt12. Since didt is negative so the value of numerator will be more than 6 V and hence current in the circuit at that instant will be more than 0.5 A.Similar Questions
What happens when the switch is turned off in the adjoining figure which shows two bulbs B1 and B2, resistor R and an inductor L ?
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