In the circuit shown, sliding contact is moving with uniform velocity towards right. Its value at some instance is 12Ω. The current in the circuit at this instant of time will be
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a
0.5 A
b
more than 0.5 A
c
less than 0.5 A
d
may be less or more than 0.5 A depending on the value of L
answer is B.
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Detailed Solution
Since resistance of the circuit is increasing and hence current in the circuit is decreasing so didtis negative.Current in the circuit is given by i=6−Ldidt12Since di/dt is negative so the value of numerator will be more than 6 V and hence current in the circuit at that instant will be more than 0.5 A.