Questions
In the circuit shown switch S is kept open for long time. Switch is closed at t = 0, find total heat produced after closing the switch
detailed solution
Correct option is D
Before closing the switchQ=CeqV=C1C2C1+C2V1-V2Q=65×1μCInitial energy stored capacitors = Q22C1+Q22C2=6522×3+6522×2=35μJAfter closing the switch Q2=10μCQ1=18μCFinal energy stored in capacitorU=12×362+12×252U=79μJWork done by batteries = 6Q1−Q+5Q+Q2=156.8μJH= work done by battery - change in potential energy of capacitors =156.8−79−35=78.4μJTalk to our academic expert!
Similar Questions
A 600 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. What is the common potential (in V) and energy lost (in J) after reconnection?
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