Q.
In the circuit shown, the total current supplied by the battery is
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a
2 ampere
b
4 ampere
c
1 ampere
d
6 ampere
answer is B.
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Detailed Solution
6Ω and 2Ω are in parallel combination Hence, RAB=6×26+2=1.5ΩV=IR⇒6015=I [∵Req=3×33+3=96=1.5Ω]⇒I=4 A
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