In the circuit shown, the total current supplied by the battery is

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2 ampere

4 ampere

1 ampere

6 ampere

answer is B.

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Detailed Solution

6Ω and 2Ω are in parallel combination Hence, RAB=6×26+2=1.5ΩV=IR⇒6015=I [∵Req=3×33+3=96=1.5Ω]⇒I=4 A

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