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Q.

A circular beam of light of diameter d = 2 cm falls on a plane surface of glass. The angle of incidence is 60° and refractive index of glass is μ = 3/2. The diameter of the refracted beam is

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a

4.00 cm

b

3.00 cm

c

3.26 cm

d

2.52 cm

answer is C.

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Detailed Solution

Let d1 be the diameter of the refracted beam. Then,d=PQ cos 600 d1=PQ cos r dd1=2 cos r sin r = sin iμ=13⇒cos r = 23 d1=2×2×23=3.26 cm
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A circular beam of light of diameter d = 2 cm falls on a plane surface of glass. The angle of incidence is 60° and refractive index of glass is μ = 3/2. The diameter of the refracted beam is