First slide

Force on a current carrying wire placed in a magnetic field

Question

A circular coil ABCD carrying a current ‘i’ is placed in a uniform magnetic field. If the magnetic force on the segment $A B is \vec{F}$ , the force on the remaining segment BCDA is

Easy

A

$- \vec{F}$
B

$3 \vec{F}$
C

$- 3 \vec{F}$
D

$\vec{F}$

Solution

The net magnetic force on a current loop in a uniform magnetic field is always zero.
$∴ {\vec{F}}_{A B} + {\vec{F}}_{B C D A} = 0 {\bar{F}}_{B C D A} = - {\bar{F}}_{A B} = - \bar{F}$

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