A circular coil having an area of 3.14 × 10-2 m2 and 30 turns is rotated about its vertical diameter with an angular speed of 70 rad-1 in a uniform horizontal magnetic field of magnitude 5 × 10-2 T. If the coil forms a closed loop of resistance 15 Ω, what is the average power loss due to Joule heating?

Given: N = 30; A = 3.14 × 10-2 m2 ; Angular velocity (ω) = 70 rad-1; B = 5 × 10-2 T; R = 15 ΩEmf (E) = NABωE = 30 × 3.14 × 10-2 × 5 × 10-2 × 70E = 3.297 VCurrent (I) = E/RI = 3.29715I = 0.2198 AAverage power loss (P) = I2R2P = 0.21982 × 152P = 0.362 WTherefore, the average power loss due to Joule heating is 0.362 W.