A circular coil having an area of $$3.14$$ × $$10-2$$ $$m2$$ and $$30$$ turns is rotated about its vertical diameter with an angular speed of $$70$$ $$rad-1$$ in a uniform horizontal magnetic field of magnitude $$5$$ × $$10-2$$ T. If the coil forms a closed loop of resistance $$15$$ Ω, what is the average power loss due to Joule heating?

Question

Infinity Learn · Accepted Answer

Given: N $$=$$ $$30$$; A $$=$$ $$3.14$$ × $$10-2$$ $$m2$$ ; Angular velocity $$($$ω$$)$$ $$=$$ $$70$$ $$rad-1$$; B $$=$$ $$5$$ × $$10-2$$ T; R $$=$$ $$15$$ ΩEmf (E) $$=$$ NABωE $$=$$ $$30$$ × $$3.14$$ × $$10-2$$ × $$5$$ × $$10-2$$ × $$70E$$ $$=$$ $$3.297$$ VCurrent (I) $$=$$ $$E/RI$$ $$=$$ $$3.29715I$$ $$=$$ $$0.2198$$ AAverage power loss (P) $$=$$ $$I2R2P$$ $$=$$ $$0.21982$$ × $$152P$$ $$=$$ $$0.362$$ WTherefore, the average power loss due to Joule heating is $$0.362$$ W.

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