First slide

Magnetic Dipole moment

Question

A circular coil of radius 4 cm has 50 turns. In this coil a current of 2 A is flowing. It is placed in a magnetic field of 0.1 weber/ $m^{2}$ . The amount of work done in rotating it through 180° from its equilibrium position will be

Moderate

A

0.1 J
B

0.2 J
C

0.4 J
D

0.8 J

Solution

$m a g n e t i c m o m e n t d u e t o a c i r c u l a r c o i l o f n t u r n s i s M = n i A a n d w o r k d o n e t o r o t a t e b y 180^{0} w i l l b e M B (1 - C o s 180^{0}) = 2 M B W = 2 n i π r^{2} B = 2 x 50 x 2 x π x 16 x 10^{- 4} x 0.1 = 0.1 J$

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