Questions
A circular coil of radius 5 cm has 500 turns of a wire. The approximate value of the coefficient of self-induction of the coil will be
detailed solution
Correct option is A
ϕ=Li⇒NBA=LiSince magnetic field at the centre of circular coil carrying current is given by B=μ04π·2πNir∴ N·μ04π·2πNir·πr2=Li⇒L=μ0N2πr2Hence, self-inductance of a coil=4π×10-7×500×500×π×0.052=25 mHTalk to our academic expert!
Similar Questions
A coil is wound as a transformer of rectangular cross-section. If all the linear dimensions of the transformer are increased by a factor 2 and the number of turns per unit length of the coil remain the same, the self inductance increased by a factor of
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