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A circular coil of radius R and N turns has negligible resistance. As shown in the schematic figure, its two ends are connected to two wires and it is hanging by those wires with its plane being vertical. The wires are connected to a capacitor with charge Q through a switch. The coil is in a horizontal uniform magnetic field Bo parallel to the plane of the coil. When the switch is closed, the capacitor gets discharged through the coil in a very short time. By the time the capacitor is discharged fully, magnitude of the angular momentum gained by the coil will be (assume that the discharge time is so short that the coil has hardly rotated during this time)-

a
π2NQB0R2
b
πNQBoR2
c
2πNQBoR2
d
4πNQBoR2

detailed solution

Correct option is B

Torque experienced by circular loop =M→×B→ where  M→ is magnetic moment                  B→ is magnetic field ∴τ=iπR2NB0 [at the instant shown θ=π/2∴τ→dt=dL→=iπR2NB0dt=QπR2NB0     [here idt=Q]

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Similar Questions

A non-conducting non-magnetic rod having circular cross section of radius R is suspended from a rigid support as shown in the figure. A light and small coil of 300 turns is wrapped tightly at the left end of the rod where uniform magnetic field B exists in vertically downward direction.Air of density ρ hits the half of the right part of the rod with velocity V as shown in the figure. What should be current in clockwise direction (as seen from O) in the coil so that rod remains horizontal? Give answer in m A. Given

2LvπRBρ=15 A-1/2


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