A circular coil of 500 turns of wire has an enclosed area of 0.1 m2 per turn. It is kept perpendicular to a magnetic field of induction 0.2 T and rotated by 180° about a diameter perpendicular to the field in 0.1 sec. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of 50 ohms

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0.2 C

0.4 C

2 C

4 C

answer is B.

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Detailed Solution

ΔQ=NBARcos⁡θ1−cos⁡θ2=500×0.2×0.1(cos⁡0−cos⁡180)50=0.4C

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