First slide

Faraday's law of Electromagnetic induction

Question

A circular coil of 500 turns of wire has an enclosed area of 0.1 m² per turn. It is kept pe{perpendicular to a magnetic field of induction 0.2 T and rotated by 180⁰ about a diameter perpendicular to the field in 0.1 s. How much charge will pass when the coil is connected to a galvanometer with a combined resistance of 50 ohms?

Moderate

A

0.2 C
B

0.4 C
C

2 C
D

4 C

Solution

$ΔQ = \frac{NBA}{R} ({cosθ}_{1} - {cosθ}_{2})$
$= \frac{500 \times 0 .2 \times 0 .1 (\cos 0^{0} - \cos 180^{0})}{50} = 0 .4 C$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App