First slide

Inductance

Question

In a circular conducting coil, when current increases from 2 A to 18 A in 0.05 s, the induced e.m.f. is 20 V. The self-inductance of the coil is

Easy

A

62.5 mH
B

6.25 mH
C

50 mH
D

None of these

Solution

$| e | = L \frac{di}{dt} \Rightarrow 20 = L \times \frac{(18 - 2)}{0 .05} \Rightarrow L = 62 .5 mH$

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