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In a circular conducting coil, when current increases from 2 A to 18 A in 0.05 s, the induced e.m.f. is 20 V. The self-inductance of the coil is

a
62.5 mH
b
6.25 mH
c
50 mH
d
None of these

detailed solution

Correct option is A

|e|=Ldidt⇒20=L×(18−2)0.05⇒L=62.5mH

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