Questions
A circular current carrying coil has a radius R. The distance from the center of the coil on the axis where the magnetic induction will be (1/8)th of its value at the center of the coil,
is
detailed solution
Correct option is B
Baxis=μ04π×2πIR2R2+x23/2 At centre, Bcentre =μ04π×2πIR In the given problem, μ04π×2πIR2R2+x23/2=18μ04π×2πIR or R2+x23/2=8R3 Solving, we get x=R3Talk to our academic expert!
Similar Questions
In figure, AB is a non-conducting rod. Equal charges of magnitude q are fixed at various points on the rod as shown. The rod is rotated uniformly about an axis passing through O and perpendicular to its length such that linear speed at the end A or B of the rod is 3 ms-1. Magnetic field at O is
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