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Q.

A circular disc is placed in front of a narrow source. When the point of observation is at a distance of 1 meter from the disc, then the disc covers first HPZ. The intensity at this point is I0. The intensity at a point distance 25 cm from the disc will be

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a

I1=0.531I0

b

I1=0.053I0

c

I1=53I0

d

I1=5.03I0

answer is A.

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Detailed Solution

I0=R2=R224Number of HPZ covered by the disc at b=25 cm n1b1=n2b2n2=n1b1b2=1×10.25=4Hence the intensity at this point isI=R'2=R522=R5R4×R4R3×R3R22×R222or I=[0.9]6I1=0.531 I0Hence the correct answer will be (a).

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