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A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r and thickness $\frac{t}{4}$ . The relation between moments of inertia $I_{A} a n d I_{B}$ and about the same axis is:

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IA > IB

IA = IB

IA < IB

depends on the actual values of t and r

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detailed solution

Correct option is C

mA = volume × density = πr2ρt IA = 12mAr2 = 12πr4ρtSimilarly IB = 12π(4r)4ρ(t4) = 64IAClearly IB > IA

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A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r and thickness t4. The relation between moments of inertia IA and IB and about the same axis is:

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A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r and thickness $\frac{t}{4}$ . The relation between moments of inertia $I_{A} a n d I_{B}$ and about the same axis is: