First slide
Moment of intertia
Question

A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r and thickness t4. The relation between moments of inertia IA andIB and  about the same axis is:

Easy
Solution

mA = volume × density = πr2ρt

        IA = 12mAr2 = 12πr4ρt

Similarly IB = 12π(4r)4ρ(t4) = 64IA

Clearly IB > IA

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