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Q.

A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r and thickness t4. The relation between moments of inertia IA and IB and  about the same axis is:

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a

IA > IB

b

IA = IB

c

IA < IB

d

depends on the actual values of t and r

answer is C.

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Detailed Solution

mA = volume × density = πr2ρt        IA = 12mAr2 = 12πr4ρtSimilarly IB = 12π(4r)4ρ(t4) = 64IAClearly IB > IA
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