A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r and thickness t4. The relation between moments of inertia IA and IB and about the same axis is:
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a
IA > IB
b
IA = IB
c
IA < IB
d
depends on the actual values of t and r
answer is C.
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Detailed Solution
mA = volume × density = πr2ρt IA = 12mAr2 = 12πr4ρtSimilarly IB = 12π(4r)4ρ(t4) = 64IAClearly IB > IA