Questions
A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r is made from an iron plate of thickness t/4. The relation between the moments of inertia IA and IB is
detailed solution
Correct option is C
For a solid disc ,I = 1/2 mR2m = π R2 / t ρ , where ρ = Density.: I = 1/2 (πR2 + σ) R2⇒ I t R4 .: IA = IB = (t / t/4) (r / 4r)4 = 1/64.: IA < IBTalk to our academic expert!
Similar Questions
Two discs have mass ratio 1 : 2 and diameter ratio 2 : 1, then find the ratio of their moments of inertia.
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
