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Q.

A circular disc of radius R is removed from a bigger circular disc of radius 2R, such that the circumference of the discs coincide. The centre of mass of the new disc is aR  from the centre of the bigger disc. The value of a is

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a

12

b

13

c

14

d

16

answer is B.

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Detailed Solution

shift in the  center of mass = mass removed x its commass remain=  m4x R3m4=R/3   a=1/3   (mass of a disc is proportional to R2
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