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A circular disc of radius R is removed from a bigger circular disc of radius 2R, such that the circumference of the discs coincide. The centre of mass of the new disc is aR from the centre of the bigger disc. The value of a is
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Correct option is B
shift in the center of mass = mass removed x its commass remain= m4x R3m4=R/3 a=1/3 (mass of a disc is proportional to R2
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Find the position of centre of mass of a uniform disc of radius R from which a hole of radius r is cut out. The centre of the hole is at a distance from the centre of the disc.
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