A circular disc X of radius R is made from an iron plate of thickness t and another disc f of radius 4R is made from an iron plate of thickness t4. Then the relation between the moment of inertia IX and IY is
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a
IY = 32IX
b
IY = 16IX
c
IY = IX
d
IY = 64IX
answer is D.
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Detailed Solution
MX=ρπR2t and MY=ρ16πR2(t/4)=4MXIYIX=MYRY2MXRX2=641