A circular disc X of radius R is made from an iron plate of thickness t, and another disc Y of radius $$4R$$ is made from an iron plate of thickness $$t/4$$. Then the relation between the moment of inertia lX and IY is

Question

Infinity Learn · Accepted Answer

Moment of Inertia of disc $$I=12MR2$$                                         $$=12$$$$π$$$$R2t$$ρ$$R2=12$$$$π$$tρ$$R4$$ [As $$M=V$$×ρ$$=$$π$$R2t$$ρ where $$t=$$ thickness, ρ$$=$$ density ∴ $$IyIx=tytxRyRx4$$              [ If ρ$$=$$ constant ]⇒ $$IyIx=14(4)4=64$$            Given $$Ry=4Rx$$,$$ty=tx4$$⇒ $$Iy=64Ix$$

A circular disc X of radius R is made from an iron plate of thickness t, and another disc Y of radius 4R is made from an iron plate of thickness t/4. Then the relation between the moment of inertia l_X and I_Y is

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A circular disc X of radius R is made from an iron plate of thickness t, and another disc Y of radius 4R is made from an iron plate of thickness t/4. Then the relation between the moment of inertia lX and IY is

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A circular disc X of radius R is made from an iron plate of thickness t, and another disc Y of radius 4R is made from an iron plate of thickness t/4. Then the relation between the moment of inertia l_X and I_Y is