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Q.

The circular head of a screw gauge is divided into 200 divisions and move 1mm ahead in one revolution. If the same instrument has a zero error of -0.05mm and the reading on the main scale in measuring diameter of a wire is 6mm and that on circular scale is 45 . The diameter of the wire is

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a

6.275mm

b

6.375mm

c

5.75mm

d

5.50mm

answer is A.

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Detailed Solution

L.C= Pitch Number of divisions on circular scale =1 mm200=0.005 mm=0.0005 cm Diameter of the wire =( Main scale reading + Circular scale reading × L.C. )− zero error =6 mm+45×0.005−(−0.05)=6 mm+0.225 mm+0.05 mm=6.275 mm

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