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A circular ring, made of copper wire, has area of 30 cm2 and resistance of 10 Ω. It is placed in a uniform magnetic field of induction 2 tesla with its plane perpendicular to the field. When the loop is rotated through an angle of θ about its diameter, 3 x 10-4 coulomb of charge flows through it. Then θ is

a
30o
b
45o
c
90o
d
60o

detailed solution

Correct option is D

ϕ1=AB=30×10−4×2 weber=6×10−3 weberϕ2=ABcosθ=6×10−3cosθNow charge flown, Q=ϕ1−ϕ2R⇒ϕ2=ϕ1−QR⇒6×10−3×cosθ=6×10−3−3×10−4×10⇒cosθ=3×10−36×10−3⇒θ=60o

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