A circular ring of mass $$6$$ kg and radius a is placed such that its centre lies at the origin. Two particles of masses $$2$$ kg each are placed at the intersecting points of the circle with positive $$X-axis$$ and positive $$Y-axis$$. Then, the angle made by the position vector of centre of mass of entire system with $$X-axis$$ is

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Infinity Learn · Accepted Answer

P is the position of centre of mass of particles at $$2$$ and $$3$$.Q is position of centre of mass of all three particles.                                 $$tan$$θ$$=yCMxCM=m1y1+m2y2+m3y3m1x1+m2x2+m3x3$$                                          $$=6$$×$$0+2$$×$$0+2$$×$$a6$$×$$0+2$$×$$a+2$$×$$0=1$$ or θ $$=$$ $$45$$∘

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