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Q.

A clear transparent glass sphere (μ = 1.5) of radius R is immersed in a liquid of refractive index 1.25. A parallel beam of light incident on it will converge to a point. The distance of this point from the centre  of the sphere will be

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a

-3R

b

+3R

c

-R

d

+5R

answer is B.

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Detailed Solution

μ1−u+μ2v=μ2−μ1R1.25−(−∞)+1.5v=1.5−1.25R  or  1.5v=0.25Rv=1.5R0.25=6Rμ2−u+μ1v=μ1−μ2R1.5−4R+12.5v=1.25−1.5−R1.25v=14R+1.54R=2.54Rv=1.25×4R2.5=5R2.5v=2RDistance from centre of sphere is 3R
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