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Q.

A clock has a continuously moving second’s hand of 0.1 m length. The average acceleration of the tip of the hand (in units of  ms−2) is of the order of :

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a

10−2

b

10−1

c

10−4

d

10−3

answer is D.

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Detailed Solution

Angular speed =ω=2πT=2π3600rad/s​Centripetal Acceleration=a=ω2r=4π23600×0.1=1.1×10−3 ms−2
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