Questions
A clock which keeps correct time at , is subjected to . If coefficient of linear expansion of the pendulum is . How much will it gain or loose in time
detailed solution
Correct option is A
Time period T∝l⇒ΔTT=12Δll=12αΔθ Also according to thermal expansion l'=(1+αΔθ)Δll=α+θ. Hence ΔTT=12Δll=12αΔθ=12×12×10−6×(40−20)=12×10−5⇒ΔT=12×10−5×86400 seconds / day ∴ΔT≈10.3 seconds / dayTalk to our academic expert!
Similar Questions
A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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