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A clock with an iron pendulum keeps correct time at  150C. If the coefficient of linear expansion of iron is  0.000012/0C and the room temperature is 200C  it loses time in a day in seconds is

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By Expert Faculty of Sri Chaitanya
a
1.35
b
2.6
c
3.25
d
3.85
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detailed solution

Correct option is B

loss or gain of time by clock per day is ΔT=12αΔt×86400 second here α is coefficient of linear expansion=12x10−6/C  0;Δt is change in temperature =5C  0 ΔT=12×12×10−6×5×86400 ΔT=3×864×10−3 ΔT=2592×10−3=2.592≃2.6 seconds=time lost in a day


Similar Questions

A clock pendulum made of invar has a period of 2s at 20oC. If the clock is used in a climate where average temperature is 40oC, what correction (in seconds) may be necessary at the end of 10 days to the time given by clock? αinvar =7×107 C1,1 day =8.64×104s

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