Questions

A clock with an iron pendulum keeps correct time at $15^{0} C$ . If the coefficient of linear expansion of iron is $0.000012 /^{0} C$ and the room temperature is $20^{0} C$ it loses time in a day in seconds is

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By Expert Faculty of Sri Chaitanya

1.35

2.6

3.25

3.85

NEW

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detailed solution

Correct option is B

loss or gain of time by clock per day is ΔT=12αΔt×86400 second here α is coefficient of linear expansion=12x10−6/C 0;Δt is change in temperature =5C 0 ΔT=12×12×10−6×5×86400 ΔT=3×864×10−3 ΔT=2592×10−3=2.592≃2.6 seconds=time lost in a day

Similar Questions

A clock pendulum made of invar has a period of 2s at 20^oC. If the clock is used in a climate where average temperature is 40^oC, what correction (in seconds) may be necessary at the end of 10 days to the time given by clock? $(α_{invar} = 7 \times {10^{- 7}}^{} C^{- 1}, 1 day = 8 .64 \times 10^{4} s)$