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# A clock with an iron pendulum keeps correct time at  ${15}^{0}C$. If the coefficient of linear expansion of iron is  $0.000012{/}^{0}C$ and the room temperature is ${20}^{0}C$  it loses time in a day in seconds is

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a
1.35
b
2.6
c
3.25
d
3.85
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detailed solution

Correct option is B

loss or gain of time by clock per day is ΔT=12αΔt×86400 second here α is coefficient of linear expansion=12x10−6/C  0;Δt is change in temperature =5C  0 ΔT=12×12×10−6×5×86400 ΔT=3×864×10−3 ΔT=2592×10−3=2.592≃2.6 seconds=time lost in a day

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A clock pendulum made of invar has a period of 2s at 20oC. If the clock is used in a climate where average temperature is 40oC, what correction (in seconds) may be necessary at the end of 10 days to the time given by clock?

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