Q.

A clock with a metallic pendulum is 5 seconds fast each day at a temperature of  15∘c and 10 seconds slow each day at a temperature of  30∘c, find the coefficient of linear expansion of the metal?

Moderate

Unlock the Full Solution and Master the Concept

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya

a

2.31×10−5 ∘c-1

b

2.03×10−5 ∘c-1

c

1.03×10−6 C -1  0

d

1.03×10−5 C -1  0

answer is 1.

(Detailed Solution Below)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Graduation temperature= Tochange in time due to coefficient of linear expansion of material of pendulum is∆time = 12α(temperature difference)x86400 here α is coefficient of linear expansion of metal of pendulum5=12.α.To-15×86400----(1)10=12.α.30-To×86400----(2)on dividing eqn (1) with eqn(2) 12=T0-1530-T0 ⇒T0=200C substitute T0 vallue in eqn(1) 5=12α(20-15)86400⇒α=2.31 x 10-5 C -1  0=coefficient of linear expansion of metal
ctaimg
Choose your Grade and Exam
edit icon

Connect with our

Expert Counsellors

access to India's best teachers with a record of producing top rankers year on year.

+91

We will send a verification code via OTP.

whats app icon