A closed loop made up of insulating material, having cross-sectional area 10 cm2 is placed in a varying magnetic field which is increasing at the rate of 10T/s. The plane of the loop is perpendicular to magnetic field. Calculate the induced emf and induced current.
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answer is 2.
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Detailed Solution
ε=dϕdt=AdBdt=10×10−4×10V=10−2Vloop is of insulating material, i=0