A closed vessel contains $$8$$ g of oxygen and $$7$$ g of nitrogen. The total pressure is $$10$$ atm at a given temperature. If now oxygen is absorbed by introducing a suitable absorbent, the pressure of the remaining gas in atm will be

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From Dalton's law, final picture of the mixture of nitrogen and oxygen is μ$$1RTV+$$μ$$2RTV=m1M1RTV+m2M2RTV$$,$$=832RTV+728RTV=RT2V$$⇒$$10=RT2V$$, When oxygen is absorbed then for nitrogen let pressure is $$P=728RTV$$⇒$$P=RT4VFrom$$ Eqs. (i) and (ii). we get pressure of the nitrogen P $$=$$ $$5$$ atm

A closed vessel contains 8 g of oxygen and 7 g of nitrogen. The total pressure is 10 atm at a given temperature. If now oxygen is absorbed by introducing a suitable absorbent, the pressure of the remaining gas in atm will be

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