Questions
A closely wound flat circular coil of 25 turns of wire has diameter of 10 cm which carries current of 4 A. The flux density at the centre of a coil will be
a
1.679 × 10−5 T
b
1.256 × 10−3 T
c
1.512 × 10−5 T
d
2.28 × 10−4 T
detailed solution
Correct option is B
The magnetic field at the centre of the coil,B=μ04π 2πNiawhere N is number of turns, i is current and a is radius of coil.Given, N=25, D=10 cm =10 × 10−2 mRadius of the coil,a=D2 = 10 × 10−22 m=0.05 mAnd current i = 4 A. Putting these values in the expression for B , we get B=1.256 mTTalk to our academic expert!
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