First slide

Stationary waves

Question

A 1 cm long string vibrates with fundamental frequency of 256 Hz. If the length is reduced to $\frac{1}{4} cm$ keeping the tension unaltered, the new fundamental frequency will be (in Hz)

Easy

A

64
B

256
C

512
D

1024

Solution

$n \propto \frac{1}{l} \Rightarrow \frac{n_{2}}{n_{1}} = \frac{l_{1}}{l_{2}} \Rightarrow n_{2} = \frac{l_{1}}{l_{2}} n_{1} = \frac{1 \times 256}{1 / 4} = 1024 Hz$

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