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A 1 cm long string vibrates with fundamental frequency of 256 Hz. If the length is reduced to 14cm keeping the tension unaltered, the new fundamental frequency will be (in Hz)

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a
64
b
256
c
512
d
1024

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detailed solution

Correct option is D

n∝1l⇒n2n1=l1l2⇒n2=l1l2n1=1×2561/4=1024 Hz


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