First slide

Measurement

Question

$1 cm$ of main scale of a vernier calipers is divided into 10 divisions. The least count of the calipers is $0.005 cm$ , then the vernier scale must have

Moderate

A

10 divisions
B

20 divisions
C

25 divisions
D

50 divisions

Solution

$LC = \frac{1}{n} MSD$
Here, n= number of vernier scale divisions
$0.005 cm = \frac{1}{n} (\frac{1}{10} cm)$
$n = \frac{0.1}{0.005} = \frac{1000}{50}$
n = 20

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